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What will be the output of the following code snippet?
let x = 10;
{
console.log(x);
let x = 20;
}
let x = 10;
{
console.log(x);
let x = 20;
}
- a)10
- b)20
- c)undefined
- d)ReferenceError
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
What will be the output of the following code snippet?let x = 10;{ con...
The 'console.log(x)' line tries to access 'x' before it is declared inside the block. Since 'let' has block scope, the declaration of 'x' shadows the outer 'x' variable, and it is not accessible before its declaration.
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Community Answer
What will be the output of the following code snippet?let x = 10;{ con...
Explanation:
Variable Scope:
- When a variable is declared using the `let` keyword, it is block-scoped.
- In the given code snippet, there is a variable `x` declared outside the block and another `x` declared inside the block.
Hoisting:
- Variables declared with `let` are hoisted to the top of their block but are not initialized.
- In the code snippet, the variable `x` inside the block is hoisted to the top of the block but not initialized.
Output:
- When the `console.log(x)` statement is executed, it refers to the `x` variable declared inside the block which is not initialized yet.
- This results in a `ReferenceError` because the `x` variable inside the block is in the temporal dead zone until it is initialized.
Therefore, the output of the given code snippet will be a ReferenceError.
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What will be the output of the following code snippet?let x = 10;{ console.log(x); let x = 20;}a)10b)20c)undefinedd)ReferenceErrorCorrect answer is option 'D'. Can you explain this answer?
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